Assignment5_2

Menu Driven C++ Programs for 2D Arrays

Options:

• Input elements into the matrix of size \( m \times n \).
• Display elements of the matrix of size \( m \times n \).
• Sum of all elements of the matrix.
• Row-wise sum of the matrix.
• Column-wise sum of the matrix.
• Transpose of the matrix \( B \) of size \( n \times m \).

Answer:

void inputMatrix(int A[][MAX], int m, int n) {
    cout << "Enter elements:\n";
    for (int i = 0; i < m; i++)
        for (int j = 0; j < n; j++)
            cin >> A[i][j];
}
void displayMatrix(int A[][MAX], int m, int n) {
    for (int i = 0; i < m; i++) {
        for (int j = 0; j < n; j++)
            cout << A[i][j] << " ";
        cout << endl;
    }
}
int sumMatrix(int A[][MAX], int m, int n) {
    int sum = 0;
    for (int i = 0; i < m; i++)
        for (int j = 0; j < n; j++)
            sum += A[i][j];
    return sum;
}
                            

Write user-defined functions for:

• Left diagonal sum
• Right diagonal sum

Answer:

int leftDiagonalSum(int A[][MAX], int n) {
    int sum = 0;
    for (int i = 0; i < n; i++)
        sum += A[i][i];
    return sum;
}
int rightDiagonalSum(int A[][MAX], int n) {
    int sum = 0;
    for (int i = 0; i < n; i++)
        sum += A[i][n - i - 1];
    return sum;
}
                            

Answer:

void multiplyRowElements(int A[4][6]) {
    for (int i = 0; i < 4; i++) {
        int product = 1;
        for (int j = 0; j < 6; j++)
            product *= A[i][j];
        cout << "Row " << i + 1 << " product: " << product << endl;
    }
}
                            

Given a square matrix, display only the upper half (above and including the diagonal).

Answer:

void upperHalf(int A[][MAX], int N) {
    for (int i = 0; i < N; i++) {
        for (int j = 0; j < N; j++) {
            if (j >= i)
                cout << A[i][j] << " ";
            else
                cout << "  ";
        }
        cout << endl;
    }
}
                

For a square matrix with odd dimensions (e.g., \( 3 \times 3 \), \( 5 \times 5 \)), display:

• Middle row
• Middle column

Answer:

void displayMiddle(int A[][MAX], int N) {
    int middle = N / 2;
    cout << "Middle Row: ";
    for (int i = 0; i < N; i++)
        cout << A[middle][i] << " ";
    cout << "\nMiddle Column: ";
    for (int i = 0; i < N; i++)
        cout << A[i][middle] << " ";
    cout << endl;
}
                

Answer:

void addMatrices(int A[][MAX], int B[][MAX], int C[][MAX], int m, int n) {
    for (int i = 0; i < m; i++) {
        for (int j = 0; j < n; j++) {
            C[i][j] = A[i][j] + B[i][j];
        }
    }
    cout << "Sum of matrices:\n";
    for (int i = 0; i < m; i++) {
        for (int j = 0; j < n; j++) {
            cout << C[i][j] << " ";
        }
        cout << endl;
    }
}
                

Answer:

void multiplyMatrices(int A[][MAX], int B[][MAX], int C[][MAX], int N, int L, int M) {
    for (int i = 0; i < N; i++) {
        for (int j = 0; j < M; j++) {
            C[i][j] = 0;
            for (int k = 0; k < L; k++) {
                C[i][j] += A[i][k] * B[k][j];
            }
        }
    }
    cout << "Product of matrices:\n";
    for (int i = 0; i < N; i++) {
        for (int j = 0; j < M; j++) {
            cout << C[i][j] << " ";
        }
        cout << endl;
    }
}